8. Simple applications, percentage, rates. Many problems involving percentage and rates are easily solved by means of the slide rule. One per cent (1%) of a number N is N × 1/100; hence 5% of N is N × 5/100, and, in general, p% of N is pN/100. Hence to find 83% of 1872 to 1872 on D set right index of C, push hairline to 83 on C, at the hairline read 1554 on D. Since (83/100) × 1872 is approximately (80/100) × 2000 = 1600, the answer is 1554. To find the answer to the question "M is what per cent of N?" we must find 100 M ÷ N. Thus, to find the answer to the question "87 is what per cent of 184.7?" we must divide 87 × 100 = 8700 by 184.7. Hence push hairline to 87 on D, draw 1847 of C under the hairline, opposite index of C read 471 on D. The rough calculation (9000/200) = 45 shows that the decimal point should be placed after the 7. Hence the answer is 47.1%. For a body moving with a constant velocity, distance = rate times time. Hence if we write d for distance, r for rate, and t for time, we have d = rt, or r = d/t, or t = d/r. To find the distance traveled by a car going 33.7 miles per hour for 7.75 hours, write d = 33.7 × 7.75, and to 337 on D set right index of C, push hairline to 775 on C, at hairline read 261 on D. Since the answer is near to 8 × 30 = 240 miles, we have d = 261 miles. To find the average rate at which a driver must travel to cover 287 miles in 8.75 hours, write r = 287 ÷ 8.75, and push hairline to 287 on D, draw 875 of C under the hairline, opposite the index of C read 328 on D. Since the rate is near 280 ÷ 10 = 28, we have r = 32.8 miles per hour. ![]() (b) ![]() (c) ![]() (d) ![]() 2. What percent of (a) ![]() (b) ![]() (c) ![]() (d) ![]() 3. Find the distance covered by a body moving (a) ![]() (b) ![]() (c) ![]() 4. At what rate must a body move to cover (a) ![]() (b) ![]() (c) ![]() 5. Find the time required to move (a) ![]() (b) ![]() (c) ![]() |
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